Identify the correct trend given below: (Atomic No.: Ti = 2…

Chemistry Co-ordinatios Compounds JEE ADVANCED Previous Year Question Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: August 12, 2026

Identify the correct trend given below: (Atomic No.: Ti = 22, Cr = 24 and Mo = 42)

Δ o of [Cr(H 2 O) 6 ] 2+ < [Mo(H 2 O) 6 ] 2+ and Δ o of [Ti(H 2 O) 6 ] 3+ < [Ti(H 2 O) 6 ] 2+

Δ o of [Cr(H 2 O) 6 ] 2+ > [Mo(H 2 O) 6 ] 2+ and Δ o of [Ti(H 2 O) 6 ] 3+ > [Ti(H 2 O) 6 ] 2+

Δ o of [Cr(H 2 O) 6 ] 2+ > [Mo(H 2 O) 6 ] 2+ and Δ o of [Ti(H 2 O) 6 ] 3+ < [Ti(H 2 O) 6 ] 2+

Δ o of [Cr(H 2 O) 6 ] 2+ < [Mo(H 2 O) 6 ] 2+ and Δ o of [Ti(H 2 O) 6 ] 3+ > [Ti(H 2 O) 6 ] 2+

Text Solution

Verified by Experts

The correct answer is:

Δ o ∝ CFSE (Crystal field stabilization energy)

Δ o of [Cr(H 2 O) 6 ] 2+ < Δ o of [Mo(H 2 O) 6 ] 2+

Because here Δ o depends on Z eff & Z eff of 4d series is more than 3d series.

But Δ o of [Ti(H 2 O) 6 ] 3+ > Δ o of [Ti(H 2 O) 6 ] 2+

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